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DanielleElmas [232]
3 years ago
5

Divide 33 photos into two groups so the ratio is 4 to 7

Mathematics
1 answer:
Levart [38]3 years ago
7 0
33 photos in a 4x to 7x ratio

4x + 7x = 33
11x = 33
x = 3

33 photos can be put in a 4(3) to 7(3) ratio

which is a 12 to 21 ratio

so 12 photos on one side, and 21 on the other side to get the ratio of 4 to 7

Note:
<span>a(b) = ab = a x b = a times b</span>
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What is the relation of 2 perpendicular lines in terms of their slope?
UkoKoshka [18]

Answer:

they are opposites. for example: 3, -1/3, -4, 1/4

Step-by-step explanation:

hope this helps

7 0
3 years ago
Find the product of the given polynomials. <br> (5x + 8 – 6r) (4 + 2r – 7)<br><br><br>​
Inessa05 [86]

Answer:

-12r² + 10xr - 15x + 34r - 24

Step-by-step explanation:

1. Organize it, variables first - as well as adding constants such as 4 and -7

(5x - 6r + 8) (2r - 3)

2. Start by multiplying the 5x by (2r - 3), then -6r, followed by 8

(10xr - 15x) + (-12r^2 + 18r) + (16r - 24)

3. Simplify

10xr - 15x - 12r² + 18r + 16r - 24

4. Order by greatest to smallest factorial

-12r² + 10xr - 15x + 18r + 16r - 24

5. Combine like variables

-12r² + 10xr - 15x + 34r - 24

6 0
3 years ago
What is the area of each triangle 24 ft 20 ft
arsen [322]

ANSWER

Area of triangle = b*h/2

24*20/2

24*10

The area of this triangle is 240 ft squared

Hope it helps :)

3 0
3 years ago
Helpppppppp please!!!!!!!!!!!
fenix001 [56]

Answer:

a. (4, 13/6)

b. (4, -5/6)

c. (4,  5/6)

Step-by-step explanation:

sorry if it is not right.

6 0
3 years ago
Only 6. Please and thanks
salantis [7]

Answer:

Part a) 7.536\ m

Part b) \$34.14

Step-by-step explanation:

Part 6)

a) How much edging is needed?

we know that

To find out how much edging is needed determine the circumference of the circular garden

The circumference of the circular garden is equal to

C=\pi D

where

D is the diameter

we have

D=2.4\ m

assume

\pi =3.14

substitute

C=(3.14)(2.4)

C=7.536\ m

Part b) we know that

To find out the cost to edge the garden, multiply the length of edging plastic needed by the cost of $4.53 per meter

so

(7.536\ m)(4.53\ \$/m)=\$34.14

8 0
3 years ago
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