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lora16 [44]
3 years ago
12

Which rotation has occured if A (-4,2) moves to A (-2,-4)​

Mathematics
1 answer:
Alja [10]3 years ago
7 0

Answer:

90 degrees counter-clockwise

Step-by-step explanation:

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HELP ON NUMBER 2 PLEASE
Neporo4naja [7]

c

step by step explanation

hope this helps

5 0
3 years ago
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Forces with magnitudes of 2000 newtons and 900 newtons act on a machine part at angles of +30degrees and -45degrees respectively
mote1985 [20]

To get the resultant magnitude and direction of the forces we need to separate the force into its x and y components. For the x components it is the sum of 2000cos(30) and 900cos(45), which is 2368.4469 N. For the y components it will be the sum of 2000sin(30) and -900sin(45), the value for the second force is negative because it is pointing downwards, their sum would be 363.6038 N. The magnitude for the resultant force can be determined using the pythagorean theorem R=sqrt(2368.4469^2 + 363.6038^2) while its direction is found using tan^-1(363.6038/2368.4469). The final answer would be 2396.1946 N with an angle of 8.7279 degrees from the right side of x axis.




3 0
3 years ago
How do u show where a inqulity is true on a number line.<br><br> I forgot
Len [333]
This website should help you understand more on your question! 

http://www.sparknotes.com/math/algebra1/inequalities/section4/

Hope this helped!

:)
8 0
3 years ago
A map has a scale of 3 centimeters : 8 kilometers. If two cities are 11 centimeters apart on the map, what is the actual distanc
TEA [102]

I think the answer is 29.3km.

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Kobe Bryant is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one
aliina [53]

Answer:

b)0.83^6

probability of Kobe Bryant making all of his next 6 free throw attempts

=probability of Kobe Bryant making first free throw attempts x

probability of Kobe Bryant making second free throw attempts x

probability of Kobe Bryant making third free throw attempts x

probability of Kobe Bryant making fourth free throw attempts x

probability of Kobe Bryant making fifth free throw attempts x

probability of Kobe Bryant making sixth free throw attempts

= P(make 1) x P(make 2nd) x P(make 3rd) x P(make 4th) x P(make 5th)x P(make 6th) = 0.83^6



6 0
3 years ago
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