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jeka94
3 years ago
8

Write a possible explicit rule for the nth term of the sequence: 1/2, 2/3, 3/4, 4/5, 5/6

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
5 0
We are given the sequence 1/2, 2/3, 3/4, 4/5, 5/6. In this case, we are asked to determine the formula that represents the sequence. We can use trial and error to determine the formula. It is seen that this is not an arithmetic nor a geometric sequence. The sequence that makes sense here is A. an = n/(n + 1)
mart [117]3 years ago
4 0
I would pick A because if you look and plug in, you would get all your answers. A)an=n/(n+1) n= 1,2,3,4,5 a(1) = 1/(1+1) =1/2 a(3) = 3/(3+1) = 3/4
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Solve this equations for all real solutions 3t^2+4t+8=-6t
ra1l [238]

Answer:

t= -1.33 recurring and -2

Step-by-step explanation:

3t²+4t+8=-6t

3t²+4t+6t+8

3t²+10t+8

This is a quadratic equation, it can be solved by using either factorisation, completing the square method or formulae method. For the purpose of this question, I would be using the formulae method.

-b±√(b²-4ac)/2a

Where a=3, b= 10 and c=8

-10±√(10²-4(3)(8))/2(3)

-10±√(100-96)/6

(-10±√4)/6

(-10±2)/6

-10+2/6 or -10-2/6

-8/6 or -12/6

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8 0
3 years ago
The sum of two numbers is 58. The smaller number is 20 less than the larger number. What are the numbers?
bezimeni [28]
38 I hope that helps
6 0
3 years ago
Read 2 more answers
Daniel runs laps every day at the community track. He ran 45 minutes each day, 5 days each week, for 12 weeks. In that time, he
gizmo_the_mogwai [7]

1800 laps in 12 weeks

1800/12 = 150 laps in 1 week

150/5 = 30 laps a day

30 laps in 45 minutes

x laps in 60 minutes

x = (30*60)/45 = 40 laps per hour

5 0
3 years ago
S , U , N are collinear. Select the point that satisfies the definition of betweenness if NU + US = NS .
Arturiano [62]
Given that the line segments NU and US can also be written as line segment NS then Point U would satisfy the Definition of Betweenness. 

This simply means that Point U lies between Points N and S along the same line. 
5 0
3 years ago
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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
tia_tia [17]

p=501\cdot503\cdot\cdots\cdot597

q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601

So we have q=359,999p. Then

\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q

and the answer is D.

4 0
3 years ago
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