All categories

3 years ago

Find the slope of the line through (-1,1) and (3, -4)

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

= -5/4

Step-by-step explanation:

The slope through two points can be found by

m = (y2-y1)/(x2-x1)

= (-4-1)/(3--1)

= (-4-1)/(3+1)

= -5/4

You might be interested in

What is 18/25 as a decimal

Serga [27]

Answer: 0.72

Step-by-step explanation:

Hope that helps :)

4 0

2 years ago

Read 2 more answers

2.8*10⁶=? solve the equation, please

garri49 [273]

Answer:

2800000

Step-by-step explanation:

10^6 means 1000000

2.8 x 1000000 = 2800000

7 0

2 years ago

Out of 160 workers surveyed at a company, 37 walk to work.

Sonja [21]

A. 37/100
b. 736. 3300/160 is 20.215
20.215x37 =
736. hope this helped

5 0

3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

2 years ago

Find the circumference of the circle. Use 22/7 for pi.

11111nata11111 [884]

Answer:

Step-by-step explanation:

circumference = 2πr = 2*(22/7)*(14/2) = 44

8 0

2 years ago

Read 2 more answers