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Aleks [24]
3 years ago
5

String cheese sticks are sold in packs of 10, and celery sticks in packs of 15. Ms. Sobrino wants to give each of 30 students on

e string cheese stick and one celery stick. What is the least number or packs she should buy so there are non left over?
Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

3 packs of string cheese and 2 packs of celery

Step-by-step explanation:

10x3=30 string cheese and 15x2=30 celery

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Step-by-step explanation:

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which equation is the quadratic variation equation for the relatonship? the variable y varies directly with x^2 and y=36 when x=
svetoff [14.1K]

For this case we have a direct variation of the form:

y = kx ^ 2

Where,

  • <em>k: proportionality constant </em>

We must find the value of k.

For this, we use the following data:

y = 36\\x = 3

Therefore, replacing values we have:

36 = k (3) ^ 2

Rewriting:

36 = 9k

Clearing the value of k we have:

k = \frac {36} {9}\\k = 4

Therefore, the direct variation equation is given by:

y = 4x ^ 2

Answer:

The quadratic variation equation for the relatonship is:

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8 0
3 years ago
A custom rectangular tabletop has a length that is twice it’s width, and the tabletop measures 76 inches on its diagonal. What a
Sunny_sXe [5.5K]

Answer:

<em>The dimensions of the tabletop: Length= 67.976... inches and Width= 33.988... inches and the perimeter will be 203.929... inches.</em>

Step-by-step explanation:

Suppose, the width of the rectangular tabletop is x inch.

As the tabletop has a length that is twice it’s width, so the length will be:  2x inch.

The tabletop measures 76 inches on its diagonal.

<u>Formula for length of diagonal of rectangle</u>:  d=\sqrt{l^2+w^2}

So, the equation will be..........

76=\sqrt{(2x)^2+ x^2}\\ \\ 76=\sqrt{4x^2+x^2} \\ \\ 76=\sqrt{5x^2} \\ \\ 5x^2= 76^2= 5776\\ \\ x^2= \frac{5776}{5}=1155.2 \\ \\ x= \sqrt{1155.2} =33.988...

Thus, the width of the tabletop is 33.988... inches and the length will be:  (2×33.988...) = 67.976... inches.

The perimeter will be:  2(33.988...+ 67.976...) inches = 203.929... inches.

5 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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