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Aleks [24]
3 years ago
5

String cheese sticks are sold in packs of 10, and celery sticks in packs of 15. Ms. Sobrino wants to give each of 30 students on

e string cheese stick and one celery stick. What is the least number or packs she should buy so there are non left over?
Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

3 packs of string cheese and 2 packs of celery

Step-by-step explanation:

10x3=30 string cheese and 15x2=30 celery

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The minimum wage in 2003 was 5.15 this was w more than the minimum wage in 1996. write an expression for the minimum wage in 199
Kitty [74]
Minimum wage in 2003 was $51.5

1996 = w

Wage in 1996= $5.15 - w 


3 0
3 years ago
Mackenzie needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer
Ann [662]

Answer:

x=65

Step-by-step explanation:

Based on the given conditions, formulate: 157+3.75 X x=400.75

Rearrange unknown terms and Calculate the sum:

3.75x = 400.75 - 157

3.75x = 243.75

x=243.75 / 3.75

x=65

6 0
3 years ago
Are the polygons similar? If they are, write a similarity statement and give the scale factor. The figures are not drawn to scal
Ugo [173]
The answer is C.
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7 0
3 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
3 years ago
Sally is shopping for diapers and sees a box with 216 diapers for \$39.98 and a box with 88 diapers for \$24.99 . Which option h
Mekhanik [1.2K]
The first step is to find out the value of one diaper for each equation

39.98/216 = 0.18
Therefore one diaper is for 0.18 cents

24.99/88 = 0.28
Therefore one diaper is for 0.28 cents

At the end the first deal is better
7 0
3 years ago
Read 2 more answers
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