All categories

3 years ago

F granola costs $2.20 per pound, how much does 0.8 pound of granola cost?

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

4 0

Set up the proportion. Then cross multiply to solve for the variable.

$\frac{2.20 dollars}{1 pound} = \frac{x}{0.8 pounds}$

2.20(0.8) = 1(x)

1.76 = x

Answer: $1.76

ki77a [65]3 years ago

3 0

Answer: 1.76 $

2.20 times 0.8 is 1.76

You might be interested in

If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

6 0

2 years ago

First method: Multiply the equation for bouquet A by , and add it to the equation for bouquet C. Then multiply the equation for

irina [24]

Answer:

looking at anwser now

Step-by-step explanation:

4 0

3 years ago

What is the value of the expression 2/5+3/7

Ray Of Light [21]

Answer:

29/35

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Two integers a and b have a product of -48

ycow [4]

It’s c because I got it right on the test

3 0

3 years ago

1 /x^−1 in simplest rational form

Allushta [10]

Here is a link to help you find the answer:
https://www.khanacademy.org/math/algebra2/rational-expressions-equations-and-functions/simplify-rati...

Hope this helps!

3 0

3 years ago