Answer:
Part a) The ratio of the perimeters is ![3](https://tex.z-dn.net/?f=3)
Part b) The ratio of the areas is ![9](https://tex.z-dn.net/?f=9)
Step-by-step explanation:
Part A) What is the value of the ratio (new to original) of the perimeters?
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
z-----> the scale factor
x-----> the perimeter of the new triangle
y-----> the perimeter of the original triangle
![z=\frac{x}{y}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=3](https://tex.z-dn.net/?f=z%3D3)
substitute
![\frac{x}{y}=3](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D3)
Part B) What is the value of the ratio (new to original) of the areas?
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> the area of the new triangle
y-----> the area of the original triangle
![z^{2}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=3](https://tex.z-dn.net/?f=z%3D3)
substitute
![\frac{x}{y}=3^{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D3%5E%7B2%7D)
![\frac{x}{y}=9}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D9%7D)
Answer:
A quadrilateral has a parallelogram if one pair of opposite sides is congruent and parallel. Parallelograms are designed to have diagonals that bisect one another. When ABCD is bisected by — BD and —AC, then ABCD is a parallelogram.
Step-by-step explanation:
Answer:
5+(2)*(sq root 6)
Step-by-step explanation:
This is pretty simple, a given is that the square root of 25 is 5, so you already have one of your numbers. Since the square root of 24 is not a perfect square, it must be reduced and then added separately to 5. The sq root of 24 is reduced to 2 multiplied by the square root of 6.