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1 year ago

14

Leonard has built a crate for his car. The crate measures (x+5) ft by (x+1) fr by (2x+3) ft. Write an expression that represents

the volume in the crate in cubic feet

1 answer:

irakobra [83]1 year ago

5 0

Answer:

(x+5)(x+1)(2x+3) cubic feet

Step-by-step explanation:

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A sphere has a diameter of 22 units. What are it's radius and volume?

Kay [80]

Answer:

the answer is D

Step-by-step explanation:

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3 years ago

Read 2 more answers

Two shops sell the same brand of baked beans but in different sizes of tin.

serg [7]

Answer:

Price in shop B is cheaper by 12 p per kg

Step-by-step explanation:

<u>Shop A</u>

£5.65/5= £1.13 = 113 p

<u>Shop B</u>

£2.02/2= £1.01= 101 p

Price in shop B is cheaper by 12 p per kg

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3 years ago

Use the point (-6,-8) to give the six trigonometric functions

vfiekz [6]

You can't exactly get the trigonometric functions using a point unless it's a vector,

so tanx = -8/-6 = 4/3 and from it we can get the other functions

sinx = -4/5
cosx = -3/5
secx = -5/3
cscx = -5/4
cotx = 3/4

3 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

HELP PLEASEEEE!!!!!!!!

nikdorinn [45]

Chin is correct because 5 x $.65 is $3.25., and he multiplied by US/GB

Nadene is incorrect because she took GB/US x 5

3 0

2 years ago