Answer:
Step-by-step explanation:
If the base of the pyramid is squared,
Then, the area of the base is
A_b = s²
Where a is the side length
Given that the base has a side length of 8.2cm
Then,
A_b = 8.2² = (8.2)(8.2)
Now, the triangular side of the pyramid are identical and it has for sides,
We need to know the slant height,
Check attachment
using Pythagorean theorem
l² = h² + a²
l² = 10.3² + 4.1²
l² = 122.9
l = √122.9
l = 11.1 cm,
Now, to find the area of the four triangles
Area of a triangle is ½base × height
Now,
In the case of a pyramid the height is the slant height.
Four triangles will have an area of
A_t = 4 × ½ base × slant height
A_t = 4 × ½ × s× l
A_t = 4 (½)(8.2)(11.1)
A_t = 4(one-half (8.2)(11.1))
So, the total area is
A = A_b + A_t
A = (8.2)(8.2) + 4(one-half (8.2)(11.1))
Then, the first option is correct
Numerical value
A = (8.2)(8.2) + 4(one-half (8.2)(11.1))
A = 67.24 + 182.04
A = 249.28 cm²