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2 years ago

Hii I need help with these questions tyy!

Mathematics

2 answers:

frez [133]2 years ago

7 0

22.,,.,.,.,..,...,,,.

9966 [12]2 years ago

4 0

Answer:

(7x+2)(3x-1); (5x+4)^2 or (5x+4)(5x+4);

Step-by-step explanation:

formula to find area is L* W = A ; meaning length multiplied by width equals to the area.

21.

using the formula to find area...

l*w=a

(7x+2)(3x-1) would be your answer

btw, don't put the "=a" at the end, since it's an expression :))

22.

since the problem states that it's a square, you can just say either...

(5x+4)^2 or (5x+4)(5x+4) not sure which one your teacher accepts

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Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use 3.1

NeTakaya

Answer:

22 square feet

Step-by-step explanation:

Area of shaded region = Area of square - Area of circle. The diameter of the circle is also the length of the side of the square as the circumference of the circle is on the circumference of the square.

Area of circle = 3.14 × r × r

r = 10 ÷ 2

= 5

Area of circle = 3.14 × 5 × 5

= 78.5

Area of square = length × length

Area of square = 10 × 10

= 100

Area of shaded region = Square - Circle

= 100 - 78.5

= 21.5

= 22 (to the nearest square foot)

I hope this helps :)

7 0

3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

Point (-5,2) is reflected over the y axis . where is the new point located ?

Ierofanga [76]

Answer:

0,-7 or anywhere i guess-

Step-by-step explanation:

4 0

3 years ago

Please foil this for me

Mrac [35]

Answer:

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3 0

2 years ago

Lisa reads 1/2 of a 200 page book

alexgriva [62]

Answer: 24 days

Step-by-step explanation:

Takes her 4 days to read 1/2 of a 200 page book, or 100 pages.

4 days = 100 pages

X days = 600 pages

24 days = 600 pages

6 0

3 years ago