Answer:
Hence the<u> ions per mole</u> are:


In one mole of Li2SO3 , the number of the atoms are

Explanation:
The formula of lithium sulfite is Li2SO3.

It contain Li+ and SO3(2-) ions.This can be represented by :

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.
Hence the<u> ions per mole</u> are:


Number of atoms in lithium sulfite depends upon the<u> mass of the Li2SO3 present</u> .
Li2SO3 = 93.94 g/mole
This mass is equal to 1 mole of Li2SO3
Now<u> 1 mole</u> of any substance contain Na atoms . This is known as Avogadro Number.

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms
If other then 1 mole present then number of atoms are calculated by:

Here n = number of moles
if the mass of the compound is given then first calculate the number of moles.
Going to different website and watching different science videos on the unit you are on
Answer:
177.3kg C₂₁H₄₄
Explanation:
Based on the chemical reaction:
C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂
<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>
<em />
To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:
<em>Moles Ethene -Molar mass: 28.05g/mol-</em>
50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene
<em>Moles C₂₁H₄₄:</em>
1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄
<em>Mass C₂₁H₄₄:</em>
589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =
<h3>177.3kg C₂₁H₄₄</h3>