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tatiyna
3 years ago
11

how to calculate the formula mass of H2S2, HFO2 an keep at least one decimal place in atomic masses from the periodic table

Chemistry
1 answer:
weqwewe [10]3 years ago
3 0
H = 1.008
S = 32.066
F = 18.998
O = 15.999

(1.008 x 2) + (32.066 x 2) = 66.148 g/mol

(1.008) + (18.998) + (15.999 x 2) = 52.004

Let me know if you need any further help!

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How many atoms and ions does lithium sulfite have?
Serhud [2]

Answer:

Hence the<u> ions per mole</u> are:

Li^{+}= 2 ions

SO_{3}^{2-}(aq)= 1 ions

In one mole of Li2SO3 , the number of the atoms are

N_{a}=6.022\times 10^{23}

Explanation:

The formula of  lithium sulfite is Li2SO3.

Li_{2}SO_{3}

It contain Li+ and SO3(2-) ions.This can be represented by :

Li_{2}SO_{3}(s)\rightarrow 2Li^{+}(aq) +SO_{3}^{2-}(aq)

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.

Hence the<u> ions per mole</u> are:

Li^{+}= 2 ions

SO_{3}^{2-}(aq)= 1 ions

Number of atoms in  lithium sulfite depends upon the<u> mass of the Li2SO3 present</u> .

Li2SO3 = 93.94 g/mole

This mass is equal to 1 mole of Li2SO3

Now<u> 1 mole</u> of any substance contain Na atoms . This is known as Avogadro Number.

N_{a}=6.022\times 10^{23}

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms

If other then 1 mole present then number of atoms are calculated by:

Number\ of\ Atoms=Moles\times (N_{a})

Here n = number of moles

if the mass of the compound is given then first calculate the number of moles.

Moles=\frac{mass}{Molar\ mass}

6 0
3 years ago
How can i study for a science quiz for monday
Ket [755]
Going to different website and watching different science videos on the unit you are on

8 0
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Which group of drugs includes legal painkillers like OxyContin?
Bumek [7]
It should be narcotics 
4 0
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What is the chemical formula for H2O?
Bas_tet [7]

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IUPAC ID

Explanation:

4 0
4 years ago
Read 2 more answers
(C)
kari74 [83]

Answer:

177.3kg C₂₁H₄₄

Explanation:

Based on the chemical reaction:

C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂

<em>Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.</em>

<em />

To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:

<em>Moles Ethene -Molar mass: 28.05g/mol-</em>

50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene

<em>Moles C₂₁H₄₄:</em>

1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄

<em>Mass C₂₁H₄₄:</em>

589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =

<h3>177.3kg C₂₁H₄₄</h3>
6 0
3 years ago
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