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vredina [299]
3 years ago
10

If you start with 1.5 moles of H2O, how many moles of H4SiO4 do you make?

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

0.75moles of  H₄SiO₄

Explanation:

Given parameters:

Number of moles of H₂O  = 1.5moles

Unknown:

Number of moles of H₄SiO₄  = ?

Solution:

To solve this problem, we need to write the reaction equation first;

            SiO₂  +  2H₂O  →   H₄SiO₄

From the balanced reaction equation:

             2 moles of water will produce 1 mole of  H₄SiO₄

    So     1.5 moles of water will produce \frac{1.5}{2}   = 0.75moles of  H₄SiO₄

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2 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
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Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

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Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

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Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

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4 0
3 years ago
The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi
Ede4ka [16]

Answer:

\Delta _fH_{C_3H_8}=-102.7kJ/mol

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol

Best regards.

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3 years ago
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