2 years ago

determinar el centro y el radio de la circuferencia completando los trinomio cuadrado perfecto x2 + y2 +64x -6y +64

1 answer:

4 0

Can you take it out of spanish. I speak english

You might be interested in

svetoff [14.1K]

9.3 × 107 would be the scientific notation

3 0

2 years ago

Igoryamba

Answer:

i would say your right

Step-by-step explanation:

8 0

2 years ago

Lostsunrise [7]

Answer: 2x-6

Work Shown:

john = x

sam = x-3 since he scored 3 fewer than john

rob = 2*(sam) = 2(x-3) = 2*x-2*3 = 2x-6

7 0

1 year ago

Yanka [14]

Answer:

Step-by-step explanation:

Hope this helps :D

4 0

3 years ago

Andreyy89

$\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1$

Recall that

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

Your sums start at $i=3$ , so in order to apply these formulas directly, you need to compensate for the missing first two terms:

$\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8$

$\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52$

$\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}$

4 0

2 years ago