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4 years ago

PLZ HELP ME 100 POINT AND BRAINEST Solve the Quadratic Equation X^2 = -8x -7

Mathematics

1 answer:

quester [9]4 years ago

6 0

Answer:

B. $\displaystyle -1, -7$

Step-by-step explanation:

$\displaystyle x^2 = -8x - 7 → x^2 + 8x + 7 \\ \\ x^2 + 8x + 7 \\ [x + 1][x + 7]; -1, -7 = x$

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trasher [3.6K]

Answer:

Total area = 31.5 unit²

Step-by-step explanation:

Assume 1 block = 1 unit²

Divide diagram into 3 part

1. 5 by 5 block square

2. 2 by 2 block triangle(1)

2. 3 by 3 block triangle(2)

Area of square = side × side

Area of square = 5 × 5

Area of square = 25 unit²

Area of triangle(1) = [1/2][base][height]

Area of triangle(1) = [1/2][2][2]

Area of triangle(1) = 2 unit²

Area of triangle(2) = [1/2][base][height]

Area of triangle(2) = [1/2][3][3]

Area of triangle(2) = 4.5 unit²

Total area = Area of square + Area of triangle(1) +Area of triangle(2)

Total area = 25 unit² + 2 unit² + 4.5 unit²

Total area = 31.5 unit²

6 0

3 years ago

Help please! Will give brainliest to best CORRECT answer! You need a ladder that will reach up a 25 foot tall house when placed

timurjin [86]

Answer:b 27 feet

Step-by-step explanation:You need a ladder that will reach up a 25 foot tall house when placed 10 feet away from the house.

6 0

3 years ago

Read 2 more answers

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$