Question

Find the value of log(4) ∙ log(25) to five decimal places.

Answer 1

Answer:0.84164

Step-by-step explanation:

Given

$\log \left ( 4\right )\cdot \log \left ( 25\right )$

we know

$\log a^b=b\log a$

Applying this identity we get

$\log \left ( 2\right )^2\cdot \log \left ( 5\right )^2$

$=2\log \left ( 2\right )\times 2\log \left ( 5\right )$

$=4\times \log \left ( 2\right )\cdot \left ( 5\right )$

$=4\times 0.301029\times 0.698970$

$=0.84164$