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otez555 [7]
4 years ago
9

Point M is the midpoint of JK find JK when JM = 6x - 7 MK = 2x + 3 ​

Mathematics
1 answer:
eimsori [14]4 years ago
7 0

Answer:

JK= 8x-4

Step-by-step explanation:

This is achieved by adding JM And MK because M is the midpoint of JK.

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4. The claim is incorrect since the triangles do not meet the SAS triangle congruence criterion
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What is the product of 710 and 323?<br><br> 135<br><br> 11315<br><br> 21730<br><br> 3715
Firlakuza [10]

Answer:

I think I answer is 21730 I'm not sure tho

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化學製程中溫度的影響 為研究化學製程中溫度對產量之影響,我們在 3 種溫度下各生產 3批產品,結果如下表。請建立 ANOVA 表。在 0.05 顯著水準檢定不同的溫度是否會影響平均產量。
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Answer:

Step-by-step explanation:

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8 0
3 years ago
A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
geniusboy [140]
Assuming that the balls are not replaced; 

\frac{6}{9}* \frac{5}{8}* \frac{4}{7}* \frac{3}{6}= 5/42 

(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one). 

Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42. 

Hope I Helped :) 

4 0
3 years ago
SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you
lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

C=180-(A+B)

C=180-(21.24+27.14)

C=131.62

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.  

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

b^2=a^2+c^2

4^2=2^2+c^2

16=4+c^2

12=c^2

c=\sqrt{12}

c=2\sqrt{3}

- We can find angle C using the cosine trig identity

cos(C)=\frac{adjacent}{hypotenuse}

cos(C)=\frac{2}{4}

C=arccos(\frac{2}{4} )

C=60

- Now we can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+60)

A=30

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+34.88)

A=55.12

- We can find side a using the tangent trig identity

tan(C)=\frac{opposite-side}{adjacent-side}

tan(34.88)=\frac{7}{a}

a=\frac{7}{tan(34.88)}

a=10.04

- Now we can find side b using the Pythagorean theorem

b^2=a^2+c^2

b^2=10.04^2+7^2

b^2=149.8

b=\sqrt{149.8}

5 0
3 years ago
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