Z- score is a statistical tool that is used to determine the probability of finding a number or a value under a normal distribution plot. A normal distribution assumes that the mean is equal to zero and that the standard deviation is equal to 1. Using the z-score table, we can find the probability either on the right side or the left side. Using the table hence, we find the probability to the left of the value. The probability that is equivalent to the unknown z should be equal to 0.5 + (0.27/2) = 0.635. 0.5 comes from the assumption that the area under the curve on each side is 50% of the total. The equivalent z score is equal to z = 0.345.
Answer:
The principal amount is 5000 dollars = 3, 70,000 rupees (5000 dollars x 74 Rupees)
Rate = 2.5%
Time = 1 year
Now, on putting the values given in the formula
S.I.= 9,250 Rupees
Now we convert it into dollars by diving 9,250 rupees by 74 rupees.
We get,
9250/74 = 125 dollars
Step-by-step explanation:
Answer:
And then the percentage between 24 and 40 would be 
Step-by-step explanation:
For this problem we have the following parameters given:
And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.
From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.
We can find the number of deviations from themean for the limits with the z score formula we got:
And replacing we got:
And then the percentage between 24 and 40 would be
8.8 *10^3 (2 sig fig)
2.9 *10^3 (2 sig fig)
Answer:
5620.892145
first you just factor the problem then subtract and then get the answer.
