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Alex_Xolod [135]
3 years ago
6

CAN Someone help me out with Experimental probability.Ill give brainless​

Mathematics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

It is split into 8 equal parts, if you want to see how likely you're going to get red, look at how many red parts there are. 2. Now make it into a fraction! 2/8, but we need it to be simplified so it is 1/4.

Was that helpful?

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HELP MEEEE!!!<br><br> which of these graphs do not represent constant rates of change ?
Ganezh [65]

Answer:

Hello! Your answer would be below!

Step-by-step explanation:

Graph B)

Hope I helped! Ask me anything if you have questions!

3 0
2 years ago
Pls help! Asap brainliest to helpful answers
riadik2000 [5.3K]

Answer:

125

Step-by-step explanation:

3 0
2 years ago
A utility pole is 35 ft tall. The pole creates a 50 ft. shadow. What is the angle of elevation of the sun? Round your answer to
Ilya [14]
We can get the angle with 
tan a= opposite side / adjacent side = 35ft/ 50ft=0.7, so a = arctan(0.7)=35°
look at the image

6 0
3 years ago
What the answer fast
Dominik [7]

To solve this problem, first let x=0.933333(repeating). Then, you want to multiply both sides by 10 to get 10x = 9.33333 (repeating). Next, take equation 2 and minus equation 1 from it giving you 9x = 8.4. Finally, multiply both sides by 10 and you will get 90x = 84. Divide both sides by 90 giving x=84/90. Answer is 84/90. 84/90 can reduce to 14/15.

3 0
3 years ago
A person can pay $14 for a membership to the history museum and then go to the museum for just $5 per visit. What is the maximum
umka2103 [35]
Hi there!
First we subtract 44-14 leaving us with 30. 5x6 = 30
Therefore, a member can visit a history museum 6 times to equal a total cost of $44.
In a different situation:
If the person has already paid the $14, and that doesn’t count as a visit, then a person would have to visit a museum 8 times to get a total of $45. Considering this is a real-world problem.
I hope this helps and have a good day :) !
~Angel
8 0
3 years ago
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