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3 years ago

The diameter of a spherical basketball is 10 inches.

Mathematics

1 answer:

maksim [4K]3 years ago

6 0

Answer:

523.6

Step-by-step explanation:

Here is the equation to get that answer:

V=4/3πr3=4/3·π·53≈523.59878

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Need help badlyyyyyy

iren2701 [21]

Answer:

29 degree

because it is a linear pair and sum of Lanier pairs is 180 degree so one value is give and the other value we have to find by subtracting 151 from 180

mark me as the brainliest

4 0

3 years ago

Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i

Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

Step-by-step explanation:

Let X = r = a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = p = 0.35.

The sample selected is of size n = 12.

The random variable X follows a Binomial distribution with parameters n = 12 and p = 0.35.

The probability function of a binomial random variable is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

For X = 0 the probability is:

$P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006$

For X = 1 the probability is:

$P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037$

For X = 2 the probability is:

$P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109$

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

$E(X)=np$

The expected number of vehicles out of 12 that will tailgate is:

$E(X)=np=12\times0.35=4.2$

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

$SD(X)=np(1-p)$

The standard deviation of vehicles out of 12 that will tailgate is:

$SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\$

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0

3 years ago

A. For 3 days in July the temperatures

ASHA 777 [7]

la temperatura promedio fue de 103°

4 0

4 years ago

A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex

kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

$325 mg + 2mg+15 mg=342 mg$

The percentages of each component in the formula are:

Acetaminophen: $\frac{325mg*100}{342mg}=95.03$ %

Chlorpheniramine maleate: $\frac{2mg*100}{342mg} =0.58$ %

Dextromethorphan hydrobromide: $\frac{15mg*100}{342mg}=4.39$ %

If 1 Kg= $10^{6}$ mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

$\frac{10^{6} mg *0.58}{95.03}=6153.85 mg$

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

$\frac{10^{6}mg*100}{95.03}=1052307.7mg$