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tankabanditka [31]
4 years ago
13

How could this be simplified? steps?​

Mathematics
1 answer:
yanalaym [24]4 years ago
3 0
Type it on the website cymath.com I guarantee you you will get that correct and the steps
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In the diagram below,
sergey [27]
Can you attach a picture because this is very hard to read
5 0
3 years ago
Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
3 years ago
Find the slope of the line graphed
Andrej [43]

Answer:

I believe it is 2

7 0
3 years ago
Read 2 more answers
A function g(x) has x-intercepts at (1/2, 0) and (6, 0). which could be g(x)?
AlexFokin [52]
The x-intercepts of a function are used to express the function into factored form:
From (1/2, 0)
(x - 1/2)

From (6, 0)
(x-6)

(x - 1/2) (x-6) = 0
(2x -1)(x-6) = 0

The function is:
B. g(x) = (x – 6)(2x – 1)

5 0
3 years ago
Read 2 more answers
Use the distributive property to factor the expression below.<br> 544 y - 12 x 7
Zielflug [23.3K]
The answer is 4 (136y-21)

Explanation:

Factor 4 out of 544y.
4 (136y) - 12*7

Factor 4 out of -12*7.
4 (136y) + 4 (-3*7)

Factor 4 out of 4.
(136y) + 4 (-3*7)
4 (136y- 3*7)

Multiply -3 by 7.
4 (136y - 21)
6 0
3 years ago
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