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Nastasia [14]
3 years ago
7

Find the point slope formula of negative (-6,0) and slope of 2/3

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Answer:

y-0=\frac{2}{3}(x+6)

Step-by-step explanation:

The point-slope formula is y-y_{1}=m(x-x_{1}). Plug in the values from the given information and you have your answer.

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A dice is rolled 5 times. How many possible rolls are there? ( Determine the number of outcomes using only the fundamental count
e-lub [12.9K]

Answer:

There are 36 Possibilities.

Step-by-step explanation:

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5 0
4 years ago
Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
Anna007 [38]
The answer is not infinity. 
<span>Consider FBDs of each mass with the direction of motion of m1 as positive </span>

<span>m1*g-T=m1*a </span>

<span>T-m2*g=m2*a </span>

<span>assuming mass less cord and mass less, friction less pulley </span>
<span>the accelerations are equal </span>
<span>a=(T-m2*g)/m2 </span>

<span>m1*g-T=m1*(T-m2*g)/m2 </span>
<span>do some algebra </span>
<span>m1*g-T=m1*T/m2-m1*g </span>
<span>2*m1*g=T*(1+m1/m2) </span>
<span>2*m1*m2*g=T*(m2+m1) </span>
<span>2*m1*m2*g/(m2+m1)=T </span>
<span>now take the limit of T as m1->infinity </span>
<span>T=2*m2*g </span>

<span>this is intuitively correct since the maximum acceleration of m1 is -g, the cord transfers the acceleration to m2, which is being acted on by gravity downward and an upward acceleration of g. Therefore the maximum acceleration of m1 is 2*g upward. </span>
5 0
3 years ago
Solve: 3(1-2x) &gt; 3-6x
sweet [91]

3(1 - 2x) > 3 - 6x    use distributive property

(3)(1) + (3)(-2x) > 3 - 6x

3 - 6x > 3 - 6x    add 6x to both sides

3 > 3 FALSE

Answer: NO SOLUTION

5 0
3 years ago
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