All categories

2 years ago

What 3 digits are in the units period? 4,083,817

Mathematics

1 answer:

9966 [12]2 years ago

3 0

In the thousands place

You might be interested in

A bag contains green marbles and red marbles, 77 in total. The number of green

PilotLPTM [1.2K]

Answer:4

Step-by-step explanation: 77 in total

subtract 77 from 1 to get 76, multiplied by 4 would get you 304. and how many times would 77 go into 304. divide it from 77 and you will get 4.

4 0

3 years ago

Help meeeeeeeee answer these questions or correct them your like my human checker because calculators to check get boring

IRISSAK [1]

4 is 16.3, I don't know 5 or 6, 7 is 176, I don't know 8 or 9, 10 is 8.1, I don't know 11, and 12 is 48.
(I used a calculator, lol)

4 0

2 years ago

Solve 2 1/2 divided by 5 1/3 = 8/x

ipn [44]

$2\frac { 1 }{ 2 } \quad divided\quad by\quad 5\frac { 1 }{ 3 } \\ \\ 2\frac { 1 }{ 2 } =2+\frac { 1 }{ 2 } =\frac { 5 }{ 2 } \\ \\ 5\frac { 1 }{ 3 } =5+\frac { 1 }{ 3 } =\frac { 15+1 }{ 3 } =\frac { 16 }{ 3 } \\ \\ \\ \frac { \frac { 5 }{ 2 } }{ \frac { 16 }{ 3 } }$

We're dividing fractions, so we will flip the one in the denominator upside down and we will multiply it with the numerator.

$\frac { \frac { 5 }{ 2 } }{ \frac { 16 }{ 3 } } \quad =\quad \frac { 5 }{ 2 } \cdot \frac { 3 }{ 16 } =\frac { 5\cdot 3 }{ 2\cdot 16 } =\frac { 15 }{ 32 }$

Let's equal this too 8/x

$\frac { 15 }{ 32 } =\frac { 8 }{ x }$

Cross multiply.

$8\cdot 32=15\cdot x\\ \\ 256=15x$

Divide both sides by 15.

$\frac { 256 }{ 15 } =\frac { 15x }{ 15 } \\ \\ \frac { 256 }{ 15 } =x$

4 0

2 years ago

Music Jeremy spent $33 on 3 CDs .At this a rate how much would 5 CDs cost

kvasek [131]

Question: Jeremy spent $33 on 3 CDs .At this a rate how much would 5 CDs cost?

Answer: I think the answer is 55$.

Hope this helps. c;

8 0

3 years ago

Read 2 more answers

I need help with this please

Nookie1986 [14]

Answer:

steps below

Step-by-step explanation:

3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)

By laws of sines: DB / sin ∠5 = x / sin ∠4

∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α

DB = (x*sin ∠5)/sin (θ-α)

= (x* sin (90°+α)) / sin (θ-α)

AD = DB*sinθ

= (x* sin (90°+α))*sinθ / sin (θ-α)

= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0

= x* cosα* sinθ / sin (θ-α)

3.2.2 Please apply Laws of sines to calculate the length

7 0

2 years ago