X*a = 244 is equation (1)
x+a = 2 is equation (2)
Solve equation (2) for 'a' to get
x+a = 2
a = 2-x
Call this equation (3)
We will plug equation (3) into equation (1)
x*a = 244
x*(a) = 244
x*(2-x) = 244
Notice how the 'a' is replaced with an expression in terms of x
Let's solve for x
x*(2-x) = 244
2x-x^2 = 244
x^2-2x+244 = 0
If we use the discriminant formula, d = b^2 - 4ac, then we find that...
d = b^2 - 4ac
d = (-2)^2 - 4*1*244
d = -972
indicating that there are no real number solutions to the equation x^2-2x+244 = 0
So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here.
If you have learned about complex numbers, then the solution set is approximately
{x = 1 + 15.588i, a = 1 - 15.588i}
which can be found through the quadratic formula
Note: it's possible that there's a typo somewhere in the problem that your teacher gave you.
You're forgetting to add how many miles did the taxi drove you, without it, this problem doesn't have a solution, you're not including how many miles were drove additionally, as well as how much money you carry in the first place bud sorry
Its the 2nd one becuase 2(-1)+2=0 witch is greater than -4.
