3. i=129; j=112
4.k=90;l=116;m=64;n=86
5.o=13;p=78;q=91
6.a=120;b=60;c=140
Can't see #7
You did 8 I believe
9.v=39;w=59;x=121
10.y=59;z=93
11.a=42;b=48;c=132
12.a=60;b=50;c=80;d=100
Answer:
The restocking level is 113 tins.
Step-by-step explanation:
Let the random variable <em>X</em> represents the restocking level.
The average demand during the reorder period and order lead time (13 days) is, <em>μ</em> = 91 tins.
The standard deviation of demand during this same 13- day period is, <em>σ</em> = 17 tins.
The service level that is desired is, 90%.
Compute the <em>z</em>-value for 90% desired service level as follows:

*Use a <em>z</em>-table for the value.
The expression representing the restocking level is:

Compute the restocking level for a 90% desired service level as follows:


Thus, the restocking level is 113 tins.
Wait is this the problem?
Word | know | Unknown
Language| 12 | x
Total | 180 | 28980
Use cross multiply:
12(28980) = 180(x)
347760 = 180x
347760/180=1932
530,000 candles were produced by the factory (rounded of course!) in that month.
Hope this helps!