If a grocer mixed 3 lbs of candy costing $1.7 per pound and 5 lbs of candy costing 90 cents per pound, what should the price of
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We have been given that the probability of a computer containing a virus P(v) is 0.15 and probability of computer containing a worm P(w) is 0.05.
We are also told that probability of computer containing either virus or worm is 0.17.
(a) To find out the probability that the computer contains both a virus and a worm we will use probability formula,
Now let us substitute our given values in this formula.
Therefore, probability that that the computer contains both a virus and a worm is 0.03.
(b) To find out the probability that the computer contains neither a virus nor a worm we will subtract the probability of computer containing both virus and worm from 1.
Therefore, probability that the computer contains neither a virus nor a worm is 0.83.