Ask question

Ask question

All categories

3 years ago

15

Please help IXL Geometry immediately!

1 answer:

user100 [1]3 years ago

7 0

Answer:

The radius is 4 feet

Step-by-step explanation:

<u>Area of a circle: A = π * r^2</u>

<u />

<u>Step 1: Solve for r</u>

16π / π = π * r^2 / π

sqrt(16) = sqrt(r^2)

<em>4 = r</em>

<em />

Answer: The radius is 4 feet

You might be interested in

Divide. Show your work.<br><br> (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

3 years ago

Let f(x) = 4x – 5 and g(x) = 3x + 7. Find f(x) + g(x) and state its domain.

lesantik [10]

$f(x)=4x-5,\ g(x)=3x+7\\\\f(x)+g(x)=(4x-5)+(3x+7)=4x-5+3x+7\\\\=(4x+3x)+(-5+7)=7x+2\\\\\text{It's a linear function. The domain is the set of all real numbers.}\\\\Answer:\\\\f(x)+g(x)=7x+2\\D=\mathbb{R}$

8 0

4 years ago

What is this symbol called plz answer urgent

Svetlanka [38]

AB is congruent to AC that is ur Answer

5 0

3 years ago

iogann1982 [59]

Answer:

THE ANSWER IS B

Step-by-step explanation:

NO EXPLANATION JUST TRUST ME

5 0

3 years ago

These tables of values represent continuous functions. In which table do the values represent an exponential function?

vichka [17]

Answer:

The correct option is B.

Step-by-step explanation:

A function is called an exponential function if it has common ratio.

A function is called an linear function if it has common difference.

In option A.

$\frac{f(2)}{f(1)}=\frac{6}{3}=2$

$\frac{f(3)}{f(2)}=\frac{9}{6}=\frac{3}{2}$

$2\neq \frac{3}{2}$

Since the given table has different ratio, therefore it is not an exponential function. Option A is incorrect.

In option B.

$\frac{f(2)}{f(1)}=\frac{6}{2}=3$

$\frac{f(3)}{f(2)}=\frac{18}{6}=3$

$3=3$

Since the given table has common ratio, therefore it is an exponential function. Option B is correct.

In option C.

$\frac{f(2)}{f(1)}=\frac{22}{10}=\frac{11}{5}$

$\frac{f(3)}{f(2)}=\frac{34}{22}=\frac{17}{11}$

$\frac{11}{5}\neq \frac{17}{11}$

Since the given table has different ratio, therefore it is not an exponential function. Option C is incorrect.

In option D.

$\frac{f(2)}{f(1)}=\frac{8}{7}$

$\frac{f(3)}{f(2)}=\frac{9}{8}$

$\frac{8}{7}\neq \frac{9}{8}$

Since the given table has different ratio, therefore it is not an exponential function. Option D is incorrect.

3 0

3 years ago

Read 2 more answers