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Gala2k [10]
4 years ago
11

Help me with algebra homework.

Mathematics
1 answer:
Masja [62]4 years ago
4 0
The answer would be 16 if you substitute -3 for X and solve
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Help plzz I need the length of "b" and the answers and the steps to find that answer??? Plz help don't have a lot of time to sub
nadezda [96]

Answer:

Use pythagorean theorem.

Step-by-step explanation:

The length of the shorter sides are 1 & 4

1^2+4^2=c^2

1+16=c^2

17=c^2

So, the length, rounded to the nearest whole inch, would be 4.

To find the perimeter, you need to find the side lengths first.

The short sides are 6 & 7.

6^2+7^2=c^2

36+49=c^2

85=c^2

So the length for that would be 8, in the nearest whole number.

Add all of the side lengths together.

6+7+8= 21

The perimeter is 21.

8 0
3 years ago
What is a equivalent fraction for 24/30
liq [111]
There's an infinite number of equivalent fractions for 24/30 - all you need to do is to divide or multiple both numerator and denominator by the same number. For example:

24/30 = 48/60 (because 24 * 2 = 48 and 30 * 2 = 60)
24/30 = 12/15 (because 24 ÷ 2 = 12 and 30 ÷ 2 = 15)
24/30 = 72/90 (because 24 * 3 = 72 and 30 * 3 = 90)
24/30 = 4/5 (because 24 ÷ 6 = 4 and 30 ÷ 6 = 5)
etc...
6 0
3 years ago
in triangle PQR the measure of angle R=90, QP=73, RQ=55, and PR=48. what is the value of the sine of angle P to the nearest Hund
alexandr402 [8]

Answer:

P ≈ 48.89°(nearest hundredth)

Step-by-step explanation:

The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.

Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.

opposite side(QR) = 55

adjacent side(PR) = 48

hypotenuse(PQ) = 73

sin P = opposite/hypotenuse

sin P = 55/73

P = sin⁻¹ 55/73

P = sin⁻¹ 0.75342465753

P = 48.8879095605

P ≈ 48.89°(nearest hundredth)

5 0
3 years ago
The figure is a cylinder with a sphere within it.
Alenkinab [10]
Hey the answer is 2713 cm
4 0
3 years ago
Read 2 more answers
The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.
djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

where,

r_1 = radius of sphere = \frac{Diamtere}{2}=\frac{8cm}{2}=4cm

r_2 = radius of cylindrical wire = \frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

\frac{4}{3}\times r_1^3=r_2^2h

\frac{4}{3}\times (4)^3=(0.1)^2h

h=8533.33cm\approx 8533cm

Therefore, the length of the wire is, 8533 cm

6 0
3 years ago
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