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trapecia [35]
3 years ago
9

For what value of n does 216^n-2/(1/36)^3n= 216

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer is D. 1

-nyfb

Anvisha [2.4K]3 years ago
4 0

Answer:

Option (d) is correct.

for n = 1  \dfrac{216^{n-2}}{(\frac{1}{36})^{3n} }=216 holds.

Step-by-step explanation:

Given expression \dfrac{216^{n-2}}{(\frac{1}{36})^{3n} }=216

We have to find the value of n for which the given expression \dfrac{216^{n-2}}{(\frac{1}{36})^{3n} }=216

Consider the given expression  \dfrac{216^{n-2}}{(\frac{1}{36})^{3n} }=216

Apply exponent rule \frac{1}{a^b}=a^{-b}

\frac{1}{\left(\frac{1}{36}\right)^{3n}}=\left(\frac{1}{36}\right)^{-3n}

We get,

216^{n-2}\left(\frac{1}{36}\right)^{-3n}=216

Convert 216^{n-2} to base 6, we have 216^{n-2}=\left(6^3\right)^{n-2}

Thus, the expression becomes,

\left(6^3\right)^{n-2}\left(6^{-2}\right)^{-3n}=216

Apply exponent rule , \left(a^b\right)^c=a^{bc}

We get,

6^{3\left(n-2\right)}\cdot \:6^{-2\left(-3n\right)}=6^{3\left(n-2\right)-2\left(-3n\right)}

6^{3\left(n-2\right)-2\left(-3n\right)}=216

\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)

3\left(n-2\right)-2\left(-3n\right)=3

Simplify for n , we have,

n = 1

Thus for n = 1  \dfrac{216^{n-2}}{(\frac{1}{36})^{3n} }=216 holds.

 

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