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Papessa [141]
3 years ago
7

The product of 7 and a number,

Mathematics
1 answer:
andriy [413]3 years ago
4 0
Answer— 2




Explanation- simple math
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How many 3 digit multiples of both 4 and 6 are there?
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Answer: There 225 3-digit numbers multiple of 4

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Help a person out would ya...no links
Sati [7]

Answer:

72.25

Step-by-step explanation:

12.5 x 8.5 = 106.25

5 x 6.75 = 33.75

106.25- 33.75 = 72.25

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3 years ago
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Which system of equations could be used to determine how many of each coin you have
kirza4 [7]
<h3>Answer: Choice A</h3>

0.10d + 0.05n = 2.25

d = 2n

================================================

Explanation:

n = number of nickels

d = number of dimes

we have twice as many dimes as nickels, so we could have something like 18 dimes and 9 nickels. Algebraically we would write d = 18 and n = 9. The equation that fits this is d = 2n. The answer is between A and B at this point.

We rule out choice B since the 0.05d is incorrect. It should be 0.10d to represent the total value of all the dimes.

Choice A is correct

d = number of dimes

0.10d = value of all the dimes in dollars

n = number of nickels

0.05n = value of all the nickels in dollars

0.10d + 0.05n = total value from both coins combined

2.25 =  total value from both coins combined

0.10d + 0.05n = 2.25

8 0
3 years ago
A problem on a multiple-choice quiz is answered correctly with probability 0.9 if a student is prepared. An unprepared student g
lions [1.4K]

Answer:

0.08475

Step-by-step explanation:

The question above is a application of conditional probability.

The formula to use is Baye's Theorem for conditional probability.

From the above question we have the following information:

Probability of answering correctly when prepared = 0.9

Probability of not answering correctly when prepared = 1 - 0.9 = 0.1

Probability of choosing the right answer = 1/4 = 0.25

Probability of choosing the wrong answer = 1 - 0.25 = 0.75

Number of students that prepare for the quiz = 75% = 0.75

Therefore number of students that did not prepare for the quiz = 1 - 0.75

= 0.25

Hence,

The probability of not preparing but choosing the correct answer =

P[ not prepared | correct answer ]

Is calculated as :

P[ not prepared | correct answer ] =

(0.25 × 0.25)/(0.25 × 0.25) + (0.25 × 0.9)

= 0.08475

Therefore, the chance that Mr X did not prepare for the quiz but he gives the right answer = 0.08475

3 0
3 years ago
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