X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
Answer:
The answer is (1,2) I'm pretty sure that is the answer if it is not please tell me I'll check.
Greatest common factor can be also said by highest common factor it is the highest common factor of 2 numbers for
Answer:
55/4
Explanation:
Let's solve your equation step-by-step.
4
/5x−8=3
Step 1: Add 8 to both sides.
4
/5x−8+8=3+8
4
/5
x = 11
Step 2: Multiply both sides by 5/4.
(
5
/4
)*(
4
/5
x)=(
5
/4
)*(11)
x= 55/4
Answer:
x=
55
/4
Hope that helps :)
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
