Answer:
<u> -54.5%</u>
Step-by-step explanation:
You will have to use this formula
When substituted in you have
30-66=-36
-36/66= -0.54 (54 repeating)
Then you have to convert this into a percentage, -54.54(repeating) percent
To the nearest hundredth you would round down to<u> -54.5%</u>.
It is a Decrease because it is negatated.
Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = = 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
Answer:
The probability that a part is good given that it passed the inspection machine is P=0.978.
Step-by-step explanation:
As the inspection machine detect and discard any part that is completely defective, only the good and partially defective parts passed this inspection.
Then, if we have:
Probability of being a good part P(G)=0.90
Probability of being a patially defective part P(P)=0.02
Probability of being a completely defective part P(D)=0.08.
Probability of passing the inspection machine = 1-P(D)=1-0.08=0.92
Then, the probability of having a good part, given that it passed the inspection machine is: