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egoroff_w [7]
3 years ago
5

Քɛօքlɛ

Mathematics
1 answer:
rjkz [21]3 years ago
7 0
27x2+12x
By the way the 2 is meant to be 27x squared but I don't know how to get the symbol
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3x+2.2is equal to x=1.7
Leviafan [203]

Answer:

7.3 answer

Step-by-step explanation:

x=1.7

now

3x+2.2

3×1.7+2.2

7.3

7 0
3 years ago
A cup is 6.4 cm tall, not including a 0.6 cm lip. Cups are stacked inside one another. You may want to draw a diagram to help yo
Tasya [4]
If you think about how it works when cups are stacked. you will begin with the height of the cup plus the height of the lip you would then add just the heigt of the lips until you get to the height needed. so your answer should be 19 cups
0 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
I need the correct answer
vredina [299]

Answer:

x = 180 - (37 + 53)

Hope that helps


7 0
3 years ago
Read 2 more answers
Which of the following is a solution of y &gt; |x| - 6?<br><br> (-5, 1)<br> (-1, -5)<br> (5, -1)
levacccp [35]
Absolute value of x minus 6 is less than y
one way is to jsut make all the x's positive, then subtract them from 6 and see if they are less

sorry for confusing, just read below

(-5,1)
1>|-5|-6
1>5-6
1>-1
true

(-1,-5)
-5>|-1|-6
-5>1-6
-5>-5
false

(5,-1)
-1>|5|-6
-1>-1
false



answer is (-5,1)
4 0
3 years ago
Read 2 more answers
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