8/5 or 1.6 you just need to find the rise over the run
Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point
Answer:
Step-by-step explanation:
Given
Express the given point P as a unit tangent vector:
Next, find the gradient of P and T using: 
Where
So: the gradient becomes:
![\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]](https://tex.z-dn.net/?f=%5Ctriangle%20T%20%3D%20%5B%28sin%20%5Csqrt%203%29i%20%2B%20%28cos%20%5Csqrt%203%29j%5D%20%2A%20%20%5B%5Cfrac%7B%5Csqrt%203%7D%7B2%7Di%20-%20%5Cfrac%7B1%7D%7B2%7Dj%5D)
By vector multiplication, we have:
Hence, the rate is:
It should be 1/4 because one third of three fourths is one fourth. I hope this helps!
Both linear and proportional because as x increases y decreases at the same rate
Answer:
<h2>h(x) = 14</h2>
Step-by-step explanation:
f(x) + n - translation n units up
f(x) - n - translation n units down
f(x + n) - translation n units to the left
f(x - n) - translation n units to the right
===========================================
g(x) = 21
translation 7 units down: g(x) - 7 = 21 - 7 = 14
