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Zina [86]
2 years ago
11

Write the quadratic equation whose roots are -4 and 6 and whose leading coefficient is 3​

Mathematics
2 answers:
Svetach [21]2 years ago
3 0

Answer:

y = 3x² - 6x - 72

Step-by-step explanation:

Since the roots are x = - 4 and x = 6 then the factors are

(x + 4) and (x - 6) and the quadratic function is

y = a(x + 4)(x - 6) ← a is a multiplier, in this case 3, so

y = 3(x + 4)(x - 6) ← expand factors and distribute by 3

y = 3(x² - 2x - 24)

y = 3x² - 6x - 72

Otrada [13]2 years ago
3 0

3x²-6x-72. The quadratic equation whose  roots are -4 and 6 with a leading coefficient of 3 is 3x²-6x-72.

The solutions of a quadratic equation are x = -4 and x = 6 with a leading coefficient of 3. The solutions are two real numbers which means that (x + 4) and (x - 6) are the factors of our unknown quadratic equation and the leading coefficient is 3.

3(x+4)(x-6)=0

Expand (x+4)(x-6):

3(x^{2} -2x-24)=0\\3x^{2} -6x-72=0 which is our quadratic equation.

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2x + 3y = 7 3x + 2y = 8
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Answer:

\boxed{\sf \ \ \ x=2, \ \ y =1 \ \ \ }

Step-by-step explanation:

Hello,

Pls post the full question next time so that we can make sure what is expected.

I assume that you want to solve for (x,y)

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