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3 years ago

I really don’t wanna go to physical therapy today, any tips on how to get out of it?

2 answers:

8 0

Answer: you really should go even if you dont feel like it at the moment. Physical therapy is there to better your physical being and in the long run it will most likely help you. I would believe it would be in your best intrest to go to it either way.

Step-by-step explanation:

I hope you have a great day and feel better :)

Stay gold

dmitriy555 [2]3 years ago

3 0

I’m sure you could act like you have a cold Or a headache. But I think the best option is going

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Write an expression to find the distance (in degrees) between the LATITUDE lines of Moscow and Brasilia. Use absolute value in y

Alona [7]

Answer: |55.75 - (-15.8)|

Step-by-step explanation:

This is the answer that they have for edmentum but you can just copy it :)

7 0

3 years ago

Read 2 more answers

Lyla is shopping for school supplies. She has $20.00 to spend. She plans to buy a package of pens for $4.98. She also wants to b

Ket [755]

<h3><em><u>Question:</u></em></h3>

Lyla is shopping for school supplies. She has $20.00 to spend. She

plans to buy a package of pens for $4.98. She also wants to buy a

calculator. All calculators are being sold for 30 percent less than the

original price. write an inequality that can be used to find the original price, x, of a calculator lyla can buy.

<h3><em><u>Answer:</u></em></h3>

$4.98+0.7x\leq 20$ inequality that can be used to find the original price, x, of a calculator lyla can buy

<h3><em><u>Solution:</u></em></h3>

Given that,

Lyla has $ 20 to spend

So she can spend entire $ 20 or less than $ 20

Total amount she has = $ 20

She plans to buy a package of pens for $4.98

Cost of package of pens = $ 4.98

She also wants to buy a calculator

Let "x" be the original price of calculator

All calculators are being sold for 30 percent less than the original price

Selling price of calculator = original price - 30 % of original price

Selling price of calculator = x - 30 % of x = x - 0.3x = 0.7x

Selling price of calculator = 0.7x

<em><u>Thus a inequality can be framed as:</u></em>

Cost of package of pens + Selling price of calculator $\leq$ 20

$4.98+0.7x\leq 20$

This means that, combined cost of package of pen and selling price of calculator must be less than or equal to the amount with Lyla ( 20 $ )

Thus the inequality is found

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3 years ago

Which of the following equations has no solutions?

hammer [34]

May. Be D

Am I right

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2 years ago

Cameras R Us has a sale for 25% off camera bags, which is a discount of $20. To find the original cost of the camera bag, Tara c

Vsevolod [243]

Answer:

It will be 2. (B) and 4. (D)

Step-by-step explanation:

I took the assignment and got it right :D

6 0

3 years ago

Read 2 more answers

Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2

kifflom [539]

Answer:

The solution of the differential equation is $y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

<u>i) Using characteristic equation:</u>

The characteristic equation method assumes that y(t)= $e^{rt}$ , where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

$y'=re^{rt}$

$y"=r^{2}e^{rt}$

$r^{2}e^{rt}+e^{rt}=0$

$(r^{2}+1)e^{rt}=0$

As $e^{rt}$ could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

$y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}$

Using Euler's formula:

$y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]$

$y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)$

$y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)$

The particular solution of the differential equation is given by:

$y(t)_{p}=ASin(2t)+BCos(2t)$

$y'(t)_{p}=2ACos(2t)-2BSin(2t)$

$y''(t)_{p}=-4ASin(2t)-4BCos(2t)$

So we use these derivatives in the differential equation:

$-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)$

$-3ASin(2t)-3BCos(2t)=Sin(2t)$

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

$y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)$

Using the initial conditions we can check that C1=5/3 and C2=2

<u>ii) Using Laplace Transform:</u>

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]= $\frac{2}{(s^{2}+4)}$

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) = $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)-2s-1= $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)= $\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}$

Y(s)= $\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}$

Y(s)= $\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}$

Using partial franction method:

$\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}$

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)= $\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}$

Y(s)= $-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}$

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[ $-\frac{1}{3} \frac{2}{s^{2}+4}$ ]-ℒ⁻¹[ $2\frac{s }{s^{2}+1}$ ]+ℒ⁻¹[ $\frac{5}{3}\frac{1}{s^{2}+1}$ ]

$y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

3 0

3 years ago