What is true about the domain and range of the function?

Mathematics

1 answer:

Zigmanuir [339]3 years ago

7 0

what are the choices

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Answer number 58 and answer it CORRECTLY please

Dmitriy789 [7]

The answer is 11 cause if you count the white cubics you get 11 and if you count the shadow with it would be 38 and there is only 11 19 28 171
but i might be wrong

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2 years ago

At the time she had $237 ,the cost of a lesson rose to &19.how many lesson can she pay for with remaining &237

ad-work [718]

12.5, just divide 237 by 19

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2 years ago

Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10

matrenka [14]

$D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
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2 years ago

① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method

hram777 [196]

Answer:

Step-by-step explanation:

$5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\ S = 9/20\\$

$Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50$

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3 years ago

Find the measure of angle A. 4x 135° 5x A

Mkey [24]

<h2>Using this equation:</h2>

 $4 \times + 5 \times + 135 = 180$ 

<h2>We can solve for X:</h2>

 $9 \times + 135 = 180 \\ 9 \times = 45 \\ \times = 45$ 

<h2>Multiply this value of x to 4 and 5 to get the other two angels.</h2>

8 0

2 years ago