Write an equation for a line that is perpendicular to the line 8x-4y=12 and passes throught the origin
1 answer:
Answer:
y= -x
Step-by-step explanation:
First, let's put the line in y=mx+b form
8x-4y=12
Subtract 8x over
-4y= -8x+12
Then divide everything by -4
y=2x-3
To find the perpendicular slope, negate the slope and flip the numerator and the denominator
Original Slope: 2/1
Flip: 1/2
Negate: -1/2
Then, use the point slop formula to find the equation of the line.
(y-)=m(x-
)
Insert (0,0) in for and -1/2 in for m
y-0= -1/2(x-0)
Distribute the -1/2
y-0= -1/2x+0
Add the 0 over
y= -1/2x
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Answer:
and
Step-by-step explanation:
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The hypotenuse is always the side opposite of the 90 degree angle (for the given triangle, the hypotenuse is 85)
Since we are looking at the angle A, the opposite side with respect to A would be the side length of 84. That leaves the side 13 as the adjacent side.
Thus, we can now write:
The correct answer is the first answer choice.