Write an equation for a line that is perpendicular to the line 8x-4y=12 and passes throught the origin
1 answer:
Answer:
y= -x
Step-by-step explanation:
First, let's put the line in y=mx+b form
8x-4y=12
Subtract 8x over
-4y= -8x+12
Then divide everything by -4
y=2x-3
To find the perpendicular slope, negate the slope and flip the numerator and the denominator
Original Slope: 2/1
Flip: 1/2
Negate: -1/2
Then, use the point slop formula to find the equation of the line.
(y-)=m(x-
)
Insert (0,0) in for and -1/2 in for m
y-0= -1/2(x-0)
Distribute the -1/2
y-0= -1/2x+0
Add the 0 over
y= -1/2x
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Answer:
x=0.450765 or x=−0.950765
Step-by-step explanation:
14x² + 7x - 6
→ Find the product, sum and factors
Product = -6
Sum = 7
Factors = No factors
→ Since there are no factors utilise the quadratic formula
→ List the values of a, b and c
a = 14
b = 7
c= -6
→ Substitute into the formula
→ Simplify
x=0.450765 or x=−0.950765