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Bess [88]
3 years ago
8

If (x-2) is a factor of x^3+kx^2 +12x-8 then k=?

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

k = - 6

Step-by-step explanation:

Since (x - 2) is a factor then x = 2 is a root

Substitute x = 2 into the polynomial and equate to zero, that is

2³ + k(2)² + 12(2) - 8 = 0

8 + 4k + 24 - 8 = 0

4k + 24 = 0 ( subtract 24 from both sides )

4k = - 24 ( divide both sides by 4 )

k = - 6

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What is f(–3) for the function f(a) = –2a2 – 5a 4?
Setler79 [48]
F(-3)
f(a) = -2a² - 5a + 4

Substitute a with its value, -3

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6 0
3 years ago
Read 2 more answers
Is this a function or not???
kow [346]

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8 0
3 years ago
In a dice game if you roll a 2, 4, or 6 you get the value of the die. If you roll as 1, 3, or 5 you lose $5. What is the expecte
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Answer: -$0.5

Step-by-step explanation:

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+ $2                 1/6

+ $4                 1/6

+ $6                 1/6

- $5                 3/6

E(X) = (2*1/6)+(4*1/6)+(6*1/6)+(-5*3/6) = -$0.5

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2 years ago
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Answer:

$300

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(5000)(2)(3/100)

=300

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3 years ago
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