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3 years ago

If (x-2) is a factor of x^3+kx^2 +12x-8 then k=?

Mathematics

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

k = - 6

Step-by-step explanation:

Since (x - 2) is a factor then x = 2 is a root

Substitute x = 2 into the polynomial and equate to zero, that is

2³ + k(2)² + 12(2) - 8 = 0

8 + 4k + 24 - 8 = 0

4k + 24 = 0 ( subtract 24 from both sides )

4k = - 24 ( divide both sides by 4 )

k = - 6

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lara31 [8.8K]

Answer:

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Step-by-step explanation:

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3 years ago