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RoseWind [281]
2 years ago
13

LENGHT OF ORBIT AND DISTANCE FROM SUN

Mathematics
1 answer:
katen-ka-za [31]2 years ago
6 0

orbit =365.256days

distance=149.60km

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Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2
pshichka [43]
a_n_+_1=-4a_n_+_2

dividing both sides by -4, we get:

a_n_+_2=- \frac{a_n_+_1}{4}

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

a_1=2

a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}

a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}

a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}



Answer: the last term is -1/32
3 0
2 years ago
a bag contains colored tils 3 tiles are red 6 tiles are green 3 tiles are blue a tile will be randomly selected from the bag wha
valkas [14]

Answer:

By:Parrain

Step-by-step explanation:

The probability that the selected tile will be green is 0.5.

The probability that a tile will be green can be calculated by the formula:

= Number of green tiles / Total number of tiles

Total number of tiles is:

= 3 + 6 + 3

= 12 tiles

Probability of picking green tile is therefore:

= 6 / 12

= 50%

= 0.50

The probability of picking a green tile is 0.50

6 0
2 years ago
Simply the following expression: 8x + 5y - 4z + 9y - 3x + 13z
oksian1 [2.3K]

Answer:

5x+14y+9z

Step-by-step explanation:

combine 8x and -3x to get 5x

combine 5y and 9y to get 13y

combine -4z and 13z to get 9z

7 0
2 years ago
Find the midpoint of the segment with the given endpoints.
andrew-mc [135]
To solve for the midpoint of the segment we use the equation that is given as:

(x1 + x2 / 2) , (y1 + y2 / 2)

For the points given,

(x1 + x2 / 2) , (y1 + y2 / 2)
(3+ 2 / 2) , (-5 + 9 / 2)
(5/2 , 2) or (2.5 , 2)

Hope this answers the question. Have a nice day. Feel free to ask more questions.
7 0
3 years ago
Read 2 more answers
Write the equation of each ellipse in standard form with the given characteristics.
Eddi Din [679]

Answer:

Step-by-step explanation:

The foci are horizontally aligned.

horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

center (h,k)

vertices (h±a,k)

length of minor axis = 2b

foci (h±c,k), c² = a²-b²

Apply your data and solve for h, k, a, and b.

foci (±3√19, 6)

h = 0

k = 6

Length of minor axis = 2b = 10

b = 5

foci (h±3√19, 6)

c = 3√19

c³ = a² - b²

171 = a² - 25

a²  = 196

x²/196 + (y-6)²/25 = 1

6 0
2 years ago
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