LENGHT OF ORBIT AND DISTANCE FROM SUN

Mathematics

1 answer:

katen-ka-za [31]3 years ago

6 0

orbit =365.256days

distance=149.60km

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-3x^{2}-21x-54 what are the zeros? (Solutions)

Irina-Kira [14]

The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

x^2+7x+18
a=1
b=7
c=18

x= $\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}$
x= $\frac{-7+/- \sqrt{49-72} }{2}$
x= $\frac{-7+/- \sqrt{-23} }{2}$
i=√-1
x= $\frac{-7+/- i\sqrt{23} }{2}$

the zerose would be
x= $\frac{-7+ i\sqrt{23} }{2}$ or $\frac{-7- i\sqrt{23} }{2}$

4 0

3 years ago

Help needed math 3 - 10 points read closely

inessss [21]

<h2>Hello!</h2>

The answer is:

The answer is the fourth option,

$f(-3)=-\frac{1}{3}$

Piecewise functions are functions that are composed by two or more expressions, the expression to use will depend of the domain or input that we need to evaluate.

We are given the piecewise function:

$\left \{ {{\frac{1}{x}, if x$