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Blizzard [7]
2 years ago
5

Lines m and n are cut by transversal l. Lines m and n are cut by transversal l. On line m where it intersects line l, 4 angles a

re created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line n where it intersects line l, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7. Which angle relationships are correct? Check all that apply. ∠1 and ∠8 are alternate exterior angles. ∠4 and ∠6 are same side interior angles. ∠5 and ∠7 are vertical angles. ∠2 and ∠8 are corresponding angles. ∠3 and ∠6 are alternate interior angles.
Mathematics
2 answers:
Semmy [17]2 years ago
5 0

∠1 and ∠8 are alternate exterior angles and ∠3 and ∠6 are alternate interior angles

step-by-step explanation:

When the transversal crosses line m and n, alternate angles are the pair of angles formed on the outside of each of the lines and opposite side of the transversal (∠1 and ∠8). However,alternate interior angles will form opposite of the transversal but inside the lines.(∠3 and ∠6 ).

Learn More

brainly.com/question/12441758

Keywords : Transversal, angles

#LearnwithBrainly

Bogdan [553]2 years ago
5 0

Answer:

a, b, e

Step-by-step explanation:

got it right on edge

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Which point represents the value of -(-2) on the number line
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4 0
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37 + 15r > or equal to 127, what is the answer?
Tpy6a [65]

Answer:

r ≥ 6

Step-by-step explanation:

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4 0
2 years ago
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Alisiya [41]

Step-by-step explanation:

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6 0
3 years ago
Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
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