Answer:
C) About 243 hits
General Formulas and Concepts:
<u>Pre-Algebra
</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
Step-by-step explanation:
<u>Step 1: Define
</u>
y = home runs
x = hits
[Best Line of Fit] y = 0.15x - 1.5
<em>We can use this to predict the average of the scatter plot.
</em>
home runs = y = 35
<u>Step 2: Solve for </u><em><u>x</u></em><u> hits</u>
-
Substitute [BLF]: 35 = 0.15x - 1.5
- Add 1.5 on both sides: 36.5 = 0.15x
- Divide 0.15 on both sides: 243.333 = x
- Rewrite: x = 243.333
Remember that this is a <em>prediction</em>. According to the best line of fit, we would need approximately ~243 to get 35 home runs.
The slope of the line is 7/4
Answer:
40$,160$ & 60
Step-by-step explanation:
First,find the equation using y-y1/ y1-y2=x-x1=x1-x2
y-0/0-20=x-0/0-3
y=20x/3
Now put the values of x& y in the equation, for the 1st one,
y=20×6/3
=40
2nd one.y=20×24/3
=160
3rd one,
400=20x/3
X=400×3/20
=60
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean salaries of college graduates
Number of sample, n = 40
Mean, u = $62, 200
Standard deviation, s = $11,766
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
62200 +/- 1.645 × 11766/√40
= 62200 +/- 1.645 × 1860.4
= 62200 +/- 3060.358
The lower end of the confidence interval is 62200 - 3060.358 =59139.642
The upper end of the confidence interval is 62200 + 3060.358 =65260.358
Therefore, with 90% confidence interval, the mean mean salaries of college graduates is between $59139.642 and $65260.358
