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2 years ago

Please help me it will mean a lot

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

3 0

Answer:

A) a=25

B) b=14

Step-by-step explanation:

A) a/5+3=8

First you need to subtract 3 from both sides.

(a/5+3)-3=(8)-3

Then simplify

a/5=5

Multiply both sides by 5

(a/5)*5=(5)*5

Then simplify

a= 25

B )3b/7-1=5

First you need to add 1 to both sides

(3b/7-1)+1=(5)+1

Simplify

3b/7=6

Multiply both sides by 7

(3b/7)*7=(6)*7

Simplify

3b=42

Divide both sides by 3

(3b)/3=(42/3)/3

Simplify

b= 14

(Brainliest???) :P

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Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2

nikitadnepr [17]

The equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down $2\frac{1}{2}$ meters. So we can write $-2\frac{1}{2}$ .

Again Eric climbed straight up $6\frac{3}{4}$ meters. So, we can write $6\frac{3}{4}$ .

Then the change = $-2\frac{1}{2}+6\frac{3}{4}$

= $-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}$

= $-\frac{5}{2} +\frac{27}{4}$

= $\frac{-(5*2)+27}{4}$

= $\frac{-10+27}{4}$

= $\frac{17}{4}$

= $\frac{4*4+1}{4}$

= $4\frac{1}{4}$

Therefore, the equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

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brainly.com/question/24116578

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1 year ago

Simplify 2-1 + 5* 4 + 11

kozerog [31]

Answer:32

Step-by-step explanation:firs we multiply 5*4 =20 .then we subtract 2-1=1 add those numbers 20+1=21 and then add 11 which equals 32

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