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lorasvet [3.4K]
2 years ago
5

Triangle lmn has sides measuring 7 meters and 6 meters and a perimeter of 16 meters. heron’s formula: area = startroot s (s minu

s a) (s minus b) (s minus c) endroot what is the area of triangle lmn? round to the nearest square meter. 3 square meters 9 square meters 28 square meters 34 square meters
Mathematics
1 answer:
FromTheMoon [43]2 years ago
5 0

Answer:

9 m²

Step-by-step explanation:

s = half the perimeter = (a+b+c)/2

the perimeter in our case is

a+b+c = 16

so, s = 16/2 = 8

and the sides are

7 m

6 m

16 - 7 - 6 = 3 m

therefore, we get

area = sqrt(8(8-7)(8-6)(8-3)) = sqrt(8×1×2×5) = sqrt(80) =

= 8.94427191... ≈ 9 m²

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wlad13 [49]
The volume is 40
8x1x5=40
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3 years ago
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Im Timed Help Pls I need help with math problem
Nady [450]

Answer:

35.36 i think

Step-by-step explanation:

40%x68=27.2

20%x27.2=5.44

27.2+5.44=32.64

68-32.64=35.36

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7 0
3 years ago
Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.
Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number 2.14 and a fraction \frac{5}{20}

Now, according to the Commutative property of Addition:

For any two numbers a and b :

a+b = b+a

So, for 2.14 and \frac{5}{20}

Let us add

2.14+\frac{5}{20}  = \frac{214}{100}  +\frac{5}{20}

                                   =\frac{214}{100}  + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100}  + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39

Also,

\frac{5}{20} + 2.14  = \frac{5}{20} + \frac{214}{100}

                                     = \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100}  + \frac{214}{100} \\ \\=  0.25 + 2.14 \\ \\ = 2.39

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Commutative Property of Addition is satisfied.


For Associated Property of Addition

Let us take two same decimal numbers 2.14 , 7.25 and a fraction \frac{5}{20}

Now, according to the Associated property of Addition:

For any three numbers a, b  and  c

a + (b+c) =(a+b) + c

So, for 2.14 , 7.25 and \frac{5}{20}

The Left hand side:

a + (b+c)

2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})

                                                         = 2.14 + (\frac{725}{100} + \frac{25 }{100})

                                                         = 2.14 + (\frac{750}{100} )

                                                        = \frac{214}{100} + \frac{750}{100}

                                                         = \frac{964}{100}

                                                        =9.64


The Right hand side:

(a + b )+c

(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}

                                                = 9.39  + \frac{5 \times 5 }{20 \times 5}

                                                = 9.39  + \frac{25}{100}

                                                = 9.39  + 0.25

                                                = 9.64


Thus,

(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Associative Property of Addition is satisfied.




8 0
3 years ago
Ali, Ben, and Cliff plant seedlings in their neighborhood park. Ali plants 40% of the total number of seedlings, Ben plants 45%
Juli2301 [7.4K]

Answer:

580 seedlings altogether.

Step-by-step explanation:

Given that,

Ali plants 40% of the total number of seedlings, Ben plants 45% of the total number of seedlings, and Cliff plants the rest of the seedlings. Cliff plants 87 seedlings.

The percentage of the seedling planted by Cliff = 100% - 45% - 40% = 15%

<em>Let x = the total number of seedlings</em>

<em />15\%\ of\ x=87\\\\x=\dfrac{87\times 100}{15}\\\\x=580

Hence, three boys plant 580 seedlings altogether.

7 0
3 years ago
4y (4y - 4) - 4 (-4 + 5 + 4y²)<br><br> please simplify &lt;3
sasho [114]

Answer:

16y - 4

Step-by-step explanation:

4y(4y - 4) - 4(- 4 + 5 + 4y^2)

16y - 16y - 4(1 + 4y^2)

16y - 16y - 4(4y^2 + 1)

16y^2 - 16y^2 + 4

16y - 4

5 0
3 years ago
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