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3 years ago

The three squares that will form a right triangle are ...?

Mathematics

1 answer:

MAVERICK [17]3 years ago

5 0

Answer:

Three squares that form right triangle:

A, E and C

Step-by-step explanation:

Area of E = 1^2 = 1

Area of A = 2.4^2 = 5.76

Area of C = 2.6^2 = 6.76

Area A + Area E = Area C

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Are 2 + 6x and 2(3x + 1) equivalent

Solnce55 [7]

✳︎ ✳︎ ✳︎ ✳︎ ✳︎ ✳︎ Hello There! :)

To determine whether the two expressions are equivalent, we take the second expression and distribute 2:

2(3x+1)

6x+2=2+6x

And now we know the two expressions are equivalent. If you look, you will remember the Commutative Property that states:

a+b=b+a

In this case, a=6x and b=2.

So we know that the two expressions are equivalent.

Hope this helps! :)

$GraceRosalia$

$***************************************************\\Brainliest?$

3 0

3 years ago

a tank has x gallons of water. ted adds 3 gallons of water into the tank. He pours the water equally into 4 smaller containers.

Doss [256]

0.75 gallons of water is in each container

5 0

3 years ago

Read 2 more answers

HELP PLEASE SOON!

kirill115 [55]

$1.\\\\\bold{v_1}=\langle2,4\rangle\qquad\bold{v_2}=\langle-1,5\rangle\\\\
\bold{v_1}\circ\bold{v_2}=2\cdot(-1)+4\cdot5=-2+20=18\qquad [\text{C}]\\\\\\
2.\\\\
\bold{v_1}= \langle2, 5\rangle\qquad \bold{v_2}= \langle4, -3\rangle\\\\\\
\bold{v_1}\circ\bold{v_2}=2\cdot4+5\cdot(-3)=8-15=-7\\\\||\bold{v_1}||=\sqrt{2^2+5^2}=\sqrt{4+25}=\sqrt{29}\\\\
||\bold{v_2}||=\sqrt{4^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5\\\\\\
$

$\cos\Theta=\dfrac{\bold{v_1}\circ\bold{v_2}}{||\bold{v_1}||\cdot||\bold{v_2}||}=\dfrac{-7}{5\cdot\sqrt{29}}\\\\\\
\cos\Theta=-\dfrac{7}{5\sqrt{29}}\quad\implies\quad\Theta=\arccos\left(-\dfrac{7}{5\sqrt{29}}\right)\\\\\\\boxed{\Theta\approx105,1^\circ}$

7 0

4 years ago

Read 2 more answers

Philip Morris wishes to determine if there is a difference between the proportion of women and proportion of men who smoke cigar

uranmaximum [27]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the women and men who smoke respectively. The population proportion of women and men who smoke would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of women and men who smoke.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 > p2

p1 - p2 > 0

it is a right tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For women

x1 = 14

n1 = 110

p1 = 14/110 = 0.13

For men,

x2 = 7

n2 = 95

p2 = 7/95 = 0.07

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (14 + 7)/(110 + 95) = 0.1

1 - pc = 1 - 0.1 = 0.9

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.13 - 0.07)/√(0.1)(0.9)(1/110 + 1/95)

z = 1.47

From the options given, the test statistic is

e. none of these is correct.

Since it is a right tailed test, we will look at the area to the right of z = 1.47. The p value would be

p value = 1 - 0.9292 = 0.078

Since alpha, 0.005 < than the p value, 0.078, then we would fail to reject the null hypothesis. Therefore, the data does not indicate that the proportion of women who smoke cigarettes is higher than the proportion of men who do at α=.005

8 0

3 years ago

The point P(8, −3) lies on the curve y = 3/(7 − x). (a) If Q is the point (x, 3/(7 − x)), use your calculator to find the slope

yan [13]

Answer:

Slope of the line $PQ is -63.434948.$