1. 7 + 15 + 12 + 5 + 5 + 10 = 54
54 x 2.5 = $135
The correct answer is $135
2. A^2 + 9^2 = 22^2
A^2 + 81 = 484
A^2 = 403
Square root of a and 403
A= 20.7
20.7 + 22 + 9 = 51.7
The correct answer is (3)
Answer:
9
Step-by-step explanation:
3^5 = 243
3^3 = 27
243 / 27 = 9
Hope this helps :)
Answer:
Speed of first plane is 350 miles per hour
Speed of second plane is 100 miles per hour
Step-by-step explanation:
Let the speed of the second plane be X
Then the speed of the first plane will be 3.5 X
Distance travelled by first plane is 9.5 *X
Distance travelled by second plane is 9.5 * 3.5 X
Difference of distance between the two plane is
miles per hour
Speed of first plane is 3.5 *100 = 350 miles per hour
Speed of second plane is 100 miles per hour
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
<span>The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate must she return if the total travel time is three hours and forty minutes?
1st leg DATA:
distance = 90 mi ; rate = 45 mph ; time = d/r = 2 hrs.
</span><span>2nd leg DATA:
distance = 90 mi ; time = [3 2/3 - 2] = 1 2/3 hrs; rate = 90/(5/3) = 54 mph
Ans: 54 mph</span>
