All categories

3 years ago

Complete the following statement given: QXR=NYC a.QX= ? b. Y=?

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

A Park has a pond shaped like a quadrilateral with all sides 18 feet long and at least one right angle. What geometric shape bes

Rom4ik [11]

I gave some examples of some quadrilaterals. The pond is most likely the shape of a square or a triangle with a right angle.

5 0

3 years ago

Alan Lewis purchased a new computer for is office using the store's installment credit plan. The computer cost $5,991.64. What a

Alla [95]

The answer is $3594.98

5 0

3 years ago

How to you divide denominators by numerators?

Degger [83]

What he are she said.

5 0

2 years ago

Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$