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3 years ago

Write a number sentence that

Mathematics

2 answers:

Gennadij [26K]3 years ago

6 0

Answer:

ok so

faf

Step-by-step explanation:

Factor 20x2 + 25x – 12x – 15 by grouping.

1. Group terms with common factors.

2. Factor the GCF from each group.

3. Write the polynomial as a product of binomials.

(20x2 – 12x) + (25x– 15)

4x(5x – 3) + 5(5x – 3)

(5x – 3)(

x +

)

Sladkaya [172]3 years ago

3 0

The associative property of addition is where you can add three numbers together, and rearrange them, but the outcome does not change

For example:
4+(6+3)=6+(3+4)

The numbers were rearranged but the sum doesn't change.

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Someone please answer not really good with math.

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

3*3^2+8/2-(4+3)=27+4-7=24

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3 years ago

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Need help on my math test. Any Answers?

nasty-shy [4]

Answer:

use symbolab

Step-by-step explanation:

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3 years ago

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Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

MAVERICK [17]

Answer:

$d.\:ellipse;\:3x^2+y^2+6x-6y+3=0$ .

Step-by-step explanation:

The given conic has equation;

$3x^2+y^2=9$

Divide through by 9.

$\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}$

$\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1$ .

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

$(-1,3)$

The translated ellipse has equation;

$\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1$ .

Clear the fraction;

$3(x+1)^2+(y-3)^2=9$ .

Expand;

$3(x^2+2x+1)+(y^2-6y+9)=9$ .

$3x^2+6x+3+y^2-6y+9=9$ .

Write in general form;

$3x^2+y^2+6x-6y+9-9+3=0$ .

$3x^2+y^2+6x-6y+3=0$ .

The correct choice is D

4 0

3 years ago

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If Tanø =a/b Find the value of sinø+cosø/sinø-cosø

inysia [295]

Answer:

$\frac{b+a}{b-a}$

Step-by-step explanation:

Tan θ = $\frac{perpendicular}{base}$ = $\frac{b}{a}$

So, Perpendicular = b, base = a

Finding hypotenuse by Pythagorean Theorem:

$c^2 = a^2+b^2$

=> So, hypotenuse = c

Sin θ = $\frac{perpendicular}{hypotenuse}= \frac{b}{c}$

Cos θ = $\frac{base}{hypotenuse}= \frac{a}{c}$

So, Now finding $\frac{sin\theta+cos\theta}{sin\theta-cos\theta}$

=> $\frac{b}{c} + \frac{a}{c}$ ÷ $\frac{b}{c} - \frac{a}{c}$

=> $\frac{b+a}{c}$ ÷ $\frac{b-a}{c}$

=> $\frac{b+a}{c} * \frac{c}{b-a}$

=> $\frac{b+a}{b-a}$

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3 years ago

Find the 7th term of the geometric sequence with the given terms.

ohaa [14]

Answer:

1. 1458

2. 500 or -500

Step-by-step explanation:

1. a4=54, a5=162

r = 162/54 = 3

a7 = a5 × r²

= 162 × 3² = 1458

2.a4=-4, a6=-100

r² = -100/-4 = 25

r = +/- 5

a7 = a6 × r

= -100 × +/- 5

= +/- 500

3 0

4 years ago