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Sladkaya [172]
3 years ago
11

Y + 5x = 37 y = -x+13 Show your work Substitution one equation

Mathematics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

x= 6

Step-by-step explanation:

In substitution, replace the y in the first equation with what y equals. In this case, y= -x+13.

-x+13 +5x= 37

4x+ 13= 37

4x= 24

x= 6

Explanation: First combination like terms, -x and 5. 5x-1x = 4x. Next, follow the opposite of PEMDAS. Adding and subtracting are last, so subtract the 13 on each side. All that's left is dividing the 4 on each side, and you're left with 6.

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X=4/5 (x+10)<br> pls ans fast!!!!!!!!!!!!!!!!!!!!1
8_murik_8 [283]

Answer:

x=40

Step-by-step explanation:

x=4(x+10)÷5

x=(4x+40)÷5

5x=4x+40

x=40

7 0
2 years ago
Order these numbers from greatest to least: -4 , 1/4 , 0 , 4 , -3 1/2 , 7/4 , 5/4
Nadya [2.5K]

Answer:-4, -3 1/2, 0, 1/4, 5/4, 7/4, 4

Step-by-step explanation: please give brainliest and thankyou

6 0
2 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
2 years ago
Which expression represents the number of equal slices for the nth member of the pattern?
shutvik [7]
Where's the picture ?
4 0
3 years ago
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