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2 years ago

PLEASE HELP ASAP! Find the area of quadrilateral ABCD in each case.

Mathematics

1 answer:

Arisa [49]2 years ago

6 0

Answer:

The area is 5 units²

Step-by-step explanation:

∵ The area of the square of side length 3 which contains

the quadrilateral ABCD = 3 × 3 = 9 units²

∵ The area of the 4 triangles on the sides of the quadrilateral ABCD

= 1/2(2)(1) + 1/2(1)(2) + 1/2(2)(1) + 1/2(1)(2) = 4 units²

∴ The area of quadrilateral ABCD = 9 - 4 = 5 units²

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Answer:

The slope-intercept form of the line equation is:

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Step-by-step explanation:

The slope-intercept form of the line equation

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where

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(3, 4)

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$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

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Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

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switch sides

$\frac{3}{2}\left(3\right)+b=4$

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subtract 9/2 from both sides

$\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}$

$b=-\frac{1}{2}$

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

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$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Therefore, the slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

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Step-by-step explanation:

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allochka39001 [22]

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