Question

What are the roots of the equation?

Answer 1

Answer:

D

Step-by-step explanation:

Given

x² + 6x - 9 = 0 (add 9 to both sides )

x² + 6x = 9

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 9 + 9

(x + 3)² = 18 ( take the square root of both sides )

x + 3 = ± $\sqrt{18}$ = ± $\sqrt{9(2)}$ = ± 3$\sqrt{2}$

Subtract 3 from both sides

x = - 3 ± 3$\sqrt{2}$ → D

Answer 2

Answer:

D

Step-by-step explanation:

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